A
Anonymous
Guest
For the newbies reading this, one of the more conterversial aspects of "my" methods is not conducting water changes. The purpose of this thread is to simply evaulate exactly how effective a 10% weekly water change is. Therefore I will just focus on that aspect of the usual advice and practices. Regardless of what is in this thread everyone will probably continue doing or not doing water changes regardless.
It is my hope that every newbie who ever walked out of a LFS with $20-50 of salt thinking that water changes will maintain trace elements reads this thread.
To evaluate the effectiveness of water changes I will consider the effects of water changes and only water changes. This is obviously not what happens in our tanks but does show how effective water changes are.
Consider:
Period starting value=PS
Period change=PC
Water value=WV
Water change amount=amt. (fraction)
By using concentrations the actual volumn is not important. The same will be true for a 10g or 2000g system. Just that a 10% water change on the 2000g requires more water is all.
Period ending value=PS+PC (start+change)
After the water change we have:
(1-amt)*(period ending value)+amt(WV)
Or
(1-amt)*(PS+PC)+amt*(WV)
The net change after the water change is the value before the water change minus the value after the water change
Period ending value-[(1-amt)*(PS+PC)+amt*(WV)]
or
(PC+PC) - [(1-amt)*(PS+PC)+amt*(WV)]
The system will converge upon the situation where the change caused by the water change equals the change the system experienced between water changes. So:
PC=(PS+PC) - [(1-amt)*(PS+PC)+amt*(WV)]
Simplifying the PS+PC on the right
PC=-(-amt)*(PS+PC)-amt*(WV)
Solving for the period starting point PS:
PC=+amt*(PS+PC)-amt*(WV)
Amt*(PS+PC)=PC+amt(WV)
Amt*PS =PC-PC*amt+amt(wv)
PS = (1/amt - 1)*PC +WV
edit:
The parameter just before the water change is easier to remember:
just before water change (PS+PC)=WV+PC/amt
So for a 10% water change just before a water change the parameter becomes the water change value+10 times the period change.
end edit
So say you want 0 something but that something is building up at 10ppm between water changes. And the replacement water has 0 somethings . Say nitrates. With a 10% water change
PS= (1/.1 - 1)*10 + 0 = (10-1)*10 = 9*10= 90
Just to check 90 goes to 100 between water changes. A 10% water change with 0 ppm water results in 90 PPM for the start of the next period.
Now consider something being consumed at 5ppm with water change water at 425.
PS=(1/.1 -1)*-5+ 425= 9*-5+425= -45+425=380
380 drops to 375. .9*375=337.5 + .1*425=42.5 337.5+42.5=380
If 1350 is in the replacement water and the system decreases at 20 between changes
Then 1170 goes to 1150
If it increases at 20 then 1530 to 1550
The point is that water changes even assuming correct replacement water will never maintain any parameter know or unknown at that value.
In order to maintain stable more constant and optimal values the system must take care of those things itself or you must replace things that are being used up. Therefore, you dose such things as calcium. What I do is basically allow things to be present which are being brought into line with plant life. But what ever you do just don't be surprised when things build up, can't be maintained, or otherwise go south, when doing water changes. Partial water changes will never correct adverse trends.
It is my hope that every newbie who ever walked out of a LFS with $20-50 of salt thinking that water changes will maintain trace elements reads this thread.
To evaluate the effectiveness of water changes I will consider the effects of water changes and only water changes. This is obviously not what happens in our tanks but does show how effective water changes are.
Consider:
Period starting value=PS
Period change=PC
Water value=WV
Water change amount=amt. (fraction)
By using concentrations the actual volumn is not important. The same will be true for a 10g or 2000g system. Just that a 10% water change on the 2000g requires more water is all.
Period ending value=PS+PC (start+change)
After the water change we have:
(1-amt)*(period ending value)+amt(WV)
Or
(1-amt)*(PS+PC)+amt*(WV)
The net change after the water change is the value before the water change minus the value after the water change
Period ending value-[(1-amt)*(PS+PC)+amt*(WV)]
or
(PC+PC) - [(1-amt)*(PS+PC)+amt*(WV)]
The system will converge upon the situation where the change caused by the water change equals the change the system experienced between water changes. So:
PC=(PS+PC) - [(1-amt)*(PS+PC)+amt*(WV)]
Simplifying the PS+PC on the right
PC=-(-amt)*(PS+PC)-amt*(WV)
Solving for the period starting point PS:
PC=+amt*(PS+PC)-amt*(WV)
Amt*(PS+PC)=PC+amt(WV)
Amt*PS =PC-PC*amt+amt(wv)
PS = (1/amt - 1)*PC +WV
edit:
The parameter just before the water change is easier to remember:
just before water change (PS+PC)=WV+PC/amt
So for a 10% water change just before a water change the parameter becomes the water change value+10 times the period change.
end edit
So say you want 0 something but that something is building up at 10ppm between water changes. And the replacement water has 0 somethings . Say nitrates. With a 10% water change
PS= (1/.1 - 1)*10 + 0 = (10-1)*10 = 9*10= 90
Just to check 90 goes to 100 between water changes. A 10% water change with 0 ppm water results in 90 PPM for the start of the next period.
Now consider something being consumed at 5ppm with water change water at 425.
PS=(1/.1 -1)*-5+ 425= 9*-5+425= -45+425=380
380 drops to 375. .9*375=337.5 + .1*425=42.5 337.5+42.5=380
If 1350 is in the replacement water and the system decreases at 20 between changes
Then 1170 goes to 1150
If it increases at 20 then 1530 to 1550
The point is that water changes even assuming correct replacement water will never maintain any parameter know or unknown at that value.
In order to maintain stable more constant and optimal values the system must take care of those things itself or you must replace things that are being used up. Therefore, you dose such things as calcium. What I do is basically allow things to be present which are being brought into line with plant life. But what ever you do just don't be surprised when things build up, can't be maintained, or otherwise go south, when doing water changes. Partial water changes will never correct adverse trends.